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Python Institute Exam PCPP-32-101 Topic 8 Question 34 Discussion

Actual exam question for Python Institute's PCPP-32-101 exam
Question #: 34
Topic #: 8
[All PCPP-32-101 Questions]

A socket object is usually created by which one of the following invocations?

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Suggested Answer: D

ElementTree is a Python built-in module that provides a simple and efficient API for parsing and creating XML data. It allows you to access and manipulate XML data in a very straightforward way, making it easy to write XML processing applications.


This statement is true because ElementTree is a module in the standard library of Python that provides an API for working with XML data. The module supports parsing XML from strings or files, creating XML trees from scratch or modifying existing ones, searching and iterating over XML elements, and writing XML data to strings or files.

Contribute your Thoughts:

Penney
1 months ago
Option A, because creating sockets is as easy as A-B-C... D is for dummies.
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Jutta
2 days ago
I agree, creating sockets is as easy as A-B-C.
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Cecilia
11 days ago
I think A is the correct option.
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Sommer
1 months ago
I'm going with B. It's simple and straight to the point, just like my coding style.
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Novella
14 days ago
User 1: I think A is the correct answer.
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Percy
1 months ago
D is clearly the wrong answer. You can't create a socket by just passing the server address. That doesn't make any sense.
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Jamal
2 months ago
I think C is the correct answer. The socket.socket() function takes three arguments: the socket domain, socket type, and the server address.
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Aleisha
3 days ago
Actually, B) socket = socket. socket (socket_number) is the correct answer.
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Casie
17 days ago
I'm pretty sure it's D) socket = socket.socket(server address).
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Nan
28 days ago
No, I think it's A) socket. socket (socket_domain, socket_type).
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Annamae
2 months ago
I agree, C is the correct answer.
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Carline
2 months ago
Option A looks right to me. The socket module has a function called socket() that takes the socket domain and type as arguments.
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Caprice
23 days ago
Great, thanks for clarifying that!
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Xuan
26 days ago
So, the correct invocation is socket.socket(socket_domain, socket_type).
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Jess
1 months ago
User 2: Yes, that's correct. The socket module has a function called socket() that takes the socket domain and type as arguments.
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Jodi
1 months ago
Yes, I agree. The socket module's socket() function takes the domain and type as arguments.
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Margot
1 months ago
I think option A is correct.
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Maxima
1 months ago
User 1: I think the answer is A) socket. socket (socket_domain, socket_type)
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Katie
2 months ago
I'm not sure, but I think D) socket = socket.socket(server address) doesn't seem right
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Miriam
2 months ago
I believe it's C) socket = socket.socket(socket_domain, socket_type, server_address)
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Ludivina
2 months ago
I think the answer is A) socket.socket(socket_domain, socket_type)
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