Deal of The Day! Hurry Up, Grab the Special Discount - Save 25% - Ends In 00:00:00 Coupon code: SAVE25
Welcome to Pass4Success

- Free Preparation Discussions

C++ Institute Exam CPP Topic 7 Question 62 Discussion

Actual exam question for C++ Institute's CPP exam
Question #: 62
Topic #: 7
[All CPP Questions]

What happens when you attempt to compile and run the following code?

#include

#include

#include

using namespace std;

class B { int val;

public:

B(int v):val(v){}

int getV() const {return val;} bool operator < (const B & v) const { return val

ostream & operator <<(ostream & out, const B & v) { out<

templatestruct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) { out<

int main() {

int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3};

vector v1(t, t+10);

sort(v1.begin(), v1.end());

for_each(v1.begin(), v1.end(), Out(cout));cout<

return 0;

}

Program outputs:

Show Suggested Answer Hide Answer
Suggested Answer: C

Contribute your Thoughts:

Selma
1 months ago
Ah, I see what they're doing here. The sort function should work just fine, and the output should be the sorted vector of B objects. Yep, B is the correct answer for sure.
upvoted 0 times
...
Leonard
2 months ago
Haha, I can already see the problem. They forgot to overload the << operator for the B class. Gotta love those pesky compilation errors!
upvoted 0 times
Ricarda
8 days ago
User3
upvoted 0 times
...
Tanesha
9 days ago
User2
upvoted 0 times
...
Gregg
22 days ago
Compilation errors can be tricky to debug sometimes.
upvoted 0 times
...
Gregg
23 days ago
Definitely, overloading the << operator is crucial for custom classes.
upvoted 0 times
...
Gregg
1 months ago
Yeah, that's a common mistake.
upvoted 0 times
...
...
Queen
2 months ago
This is a tricky one. The code includes some custom operator overloading, so it might not be as straightforward as it seems. I'll go with option B, just to be safe.
upvoted 0 times
...
Jolanda
2 months ago
Hmm, the code looks like it's trying to sort a vector of custom objects. My guess is that it will compile and run, and the output will be a sorted list of the object values.
upvoted 0 times
Nickolas
5 days ago
User 1
upvoted 0 times
...
Rosendo
13 days ago
User 2
upvoted 0 times
...
Nilsa
15 days ago
User 1
upvoted 0 times
...
Kasandra
16 days ago
Looks like the code is sorting a vector of custom objects.
upvoted 0 times
...
Ashlyn
1 months ago
The output will be a sorted list of object values.
upvoted 0 times
...
Sylvie
1 months ago
It will compile and run successfully.
upvoted 0 times
...
Gretchen
2 months ago
B) 1 2 3 4 5 6 7 8 9 10
upvoted 0 times
...
...
Aaron
2 months ago
I'm not sure, but I think the answer is B) 1 2 3 4 5 6 7 8 9 10 because the for_each function is used to output the sorted vector elements.
upvoted 0 times
...
Kami
2 months ago
I agree with Yen, the code uses the sort function to sort the vector of objects in ascending order.
upvoted 0 times
...
Yen
2 months ago
I think the answer is B) 1 2 3 4 5 6 7 8 9 10 because the code sorts the vector in ascending order.
upvoted 0 times
...
az-700  pass4success  az-104  200-301  200-201  cissp  350-401  350-201  350-501  350-601  350-801  350-901  az-720  az-305  pl-300  

Warning: Cannot modify header information - headers already sent by (output started at /pass.php:70) in /pass.php on line 77