Tibco Exam TCP-BW6 Topic 5 Question 80 Discussion

Actual exam question for Tibco's TCP-BW6 exam

Question #: 80
Topic #: 5

Which two statements are correct about fault-tolerant groups? (Choose two.)

AFault-tolerant groups implement a K of N active strategy (K member of a group is activewhile N-K members are passive).

BMembers of a fault-tolerant group are ranked by means of the specified member weight, which must be a unique value within the fault-tolerant group.

CMembers of a fault-tolerant group are ranked by means of the specified member weight. Members with equal weight are ranked by the time they joined the fault-tolerant group.

DThe members of a fault-tolerant group are ranked by means of the specified member weight. Members with equal weight are ranked by non-deterministic means opaque to programs.

EMembers of a fault-tolerant group are ranked by means of the specified member weight.

Show Suggested Answer

Suggested Answer: A, C

by Lynelle at Jan 27, 2024, 02:59 PM

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Keshia

5 days ago

Hmm, options B and D seem more accurate to me. Members are ranked by weight, and equal weights are handled by non-deterministic means. Who needs predictability when you've got randomness?

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Stephaine

13 days ago

I'm not sure about statement D. It seems a bit confusing to me. I think I'll go with A and C as the correct statements.

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Chaya

16 days ago

I agree with you, Jenelle. I also believe statement C is correct as it talks about ranking by member weight.

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Cherry

16 days ago

I think options B and C are the correct statements. Fault-tolerant groups use member weight to rank the members, and in case of equal weight, the order is determined by join time.

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Shannon

2 days ago

I agree, option B states that members are ranked by member weight, which must be unique.

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Jenelle

22 days ago

I think statement A is correct because it mentions the K of N active strategy.

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