Splunk Exam SPLK-2002 Topic 3 Question 64 Discussion

Actual exam question for Splunk's SPLK-2002 exam

Question #: 64
Topic #: 3

[All SPLK-2002 Questions]

An indexer cluster is being designed with the following characteristics:

* 10 search peers

* Replication Factor (RF): 4

* Search Factor (SF): 3

* No SmartStore usage

How many search peers can fail before data becomes unsearchable?

AZero peers can fail.

BOne peer can fail.

CThree peers can fail.

DFour peers can fail.

Show Suggested Answer

Suggested Answer: C

by Lonna at Jan 06, 2023, 09:03 AM

Limited Time Offer

25%

Off

Get Premium SPLK-2002 Questions as Interactive Web-Based Practice Test or PDF

Contribute your Thoughts:

Submit Cancel

Portia

3 days ago

I'm not sure about this one. The replication factor seems to be the key here, but I can't quite figure it out. I'll have to think about it some more.

upvoted 0 times

...

Abel

7 days ago

Well, if 4 peers fail, that means we'd still have 6 peers left, which is above the search factor of 3, so I think D) Four peers can fail is the right choice.

upvoted 0 times

...

Joana

10 days ago

Hmm, let me think about this. With 10 search peers, a replication factor of 4, and a search factor of 3, I'd say that C) Three peers can fail is the correct answer.

upvoted 0 times

...

I'm not sure, but it makes sense that if we have 10 search peers and a Replication Factor of 4, we can tolerate losing three of them before data becomes unsearchable. So, I'll go with C) Three peers can fail.

upvoted 0 times

...

Jennifer

18 days ago

I agree with Paola, because with a Replication Factor of 4 and Search Factor of 3, we can afford to lose up to three search peers.

upvoted 0 times

...

Paola

19 days ago

I think the answer is C) Three peers can fail.

upvoted 0 times

...

Splunk Exam SPLK-2002 Topic 3 Question 64 Discussion

Contribute your Thoughts:

Portia

Abel

Joana

Ettie

Jennifer

Paola