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ServiceNow Exam CIS-SM Topic 8 Question 58 Discussion

Actual exam question for ServiceNow's CIS-SM exam
Question #: 58
Topic #: 8
[All CIS-SM Questions]

Which one of the following Regular Expressions could be used to parse the value 5.2.0 from the string?

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Suggested Answer: D

Contribute your Thoughts:

Maryln
9 days ago
Option F: Version (Hopefully not 1.0.0)
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Junita
14 days ago
I'm leaning towards Option B. It's concise and covers the typical version number format.
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Vernice
26 days ago
Option A is too broad. Capturing everything between the dots won't give you the specific version numbers.
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Hershel
6 days ago
I think option B) Version\s+(\d+\.\d+\.\d+) would work best.
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Jordan
1 months ago
Option D seems a bit overkill. Splitting the version string into three separate capturing groups feels unnecessary for this use case.
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Krissy
2 days ago
I would go with option B as well, it captures the version number accurately without unnecessary complexity.
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Shenika
6 days ago
Agreed, option B seems like the most efficient choice for this task.
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Lacresha
8 days ago
I think option B) Version\\s+(\\d+\\.\\d+\\.\\d+) would work best for parsing the value 5.2.0.
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Man
1 months ago
But option B captures the specific format of the version number with digits and dots, making it more accurate
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Charlene
1 months ago
I disagree, I believe the answer is D) Version (\d+).(\d+).(\d+)
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Man
1 months ago
I think the answer is B) Version\s+(\d+\.\d+\.\d+)
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Esteban
1 months ago
I think Option B looks the most promising. It specifically targets the 'Version' keyword and a pattern of three numbers separated by dots.
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Antonio
12 days ago
I think Option B is the correct one as well. It matches the pattern of three numbers separated by dots after the 'Version' keyword.
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Audry
13 days ago
I agree, Option B seems to be the most accurate choice.
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Norah
23 days ago
I think Option B is the correct Regular Expression to extract the value 5.2.0 from the string.
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Danica
24 days ago
I agree, Option B seems like the best choice for parsing the value 5.2.0.
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Margot
1 months ago
I'm not sure, but I think D) Version (\d+).(\d+).(\d+) could also work if we want to capture each number separately
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Hillary
2 months ago
I agree with Gwenn, because it specifies the exact format of the version number
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Gwenn
2 months ago
I think the answer is B) Version\s+(\d+\.\d+\.\d+)
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