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Salesforce Exam Javascript Developer I Topic 5 Question 68 Discussion

Actual exam question for Salesforce's Javascript Developer I exam
Question #: 68
Topic #: 5
[All Javascript Developer I Questions]

Refer to code below:

console.log(0);

setTimeout(() => (

console.log(1);

});

console.log(2);

setTimeout(() => {

console.log(3);

), 0);

console.log(4);

In which sequence will the numbers be logged?

Show Suggested Answer Hide Answer
Suggested Answer: B

Contribute your Thoughts:

Miesha
2 months ago
Okay, let's do this! I'm feeling confident with B) 02431. Those setTimeout's with a 0 millisecond delay always get executed after the current synchronous code. Gotta love JavaScript's quirks, am I right?
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Brendan
11 days ago
JavaScript can be tricky sometimes, but it's always interesting to see how it works.
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Gwenn
1 months ago
Yeah, that's correct. The setTimeout with 0 millisecond delay will be executed after the synchronous code.
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Gary
1 months ago
I think you're right! The numbers will be logged in the sequence 02431.
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Callie
2 months ago
Haha, this one's a real brain-teaser! I'm gonna go with C) 02413 just to be different. Who knows, maybe the exam folks are trying to catch us out with a trick question.
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Queenie
2 months ago
Hmm, let's see... If I remember my JavaScript fundamentals, the console.log's will execute in the order they're written, and the setTimeout's will get added to the task queue. So the answer has to be B) 02431. I hope I'm right!
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Chantay
3 days ago
Yes, the setTimeout functions will be added to the task queue and executed after the initial console.log statements. B) 02431 looks like the correct sequence.
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Ashlyn
7 days ago
I agree, the setTimeout functions will be executed after the initial console.log statements, so the order should be B) 02431.
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Alton
14 days ago
That makes sense, the setTimeout functions have a delay of 0 milliseconds, so they will be executed after the initial console.log statements. B) 02431 seems correct.
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William
24 days ago
Yes, that's correct. The numbers will be logged in the order 0, 2, 4, 3, 1. Good job!
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Myong
24 days ago
I think you're right, the setTimeout functions will be added to the task queue and logged after the initial console.log statements.
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Filiberto
28 days ago
Yes, that's correct! The setTimeout functions will be executed after the initial console.log statements, following the order they were added to the task queue. So it's definitely B) 02431.
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Mila
29 days ago
I think you're right, the setTimeout functions will be added to the task queue and executed after the console.log statements. So it should be B) 02431.
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Rodrigo
2 months ago
I think you're right, the setTimeout functions will be added to the task queue and executed after the initial console.log statements. So it should be B) 02431.
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Doyle
2 months ago
Hmm, that's an interesting point. I see your rationale. Let's wait for others to share their opinions.
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Beth
2 months ago
Ah, the classic event loop conundrum! I'm pretty sure the correct answer is B) 02431. Those setTimeout's can be tricky, but I think I've got the hang of it now.
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Trevor
22 days ago
It's all about understanding how the event loop works in JavaScript.
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Tyra
29 days ago
I remember getting confused by this at first, but now it makes sense.
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Lai
1 months ago
Yeah, the setTimeout functions can mess with the order of execution.
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Danilo
1 months ago
I think you're right, it should be B) 02431.
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Cathrine
2 months ago
I disagree, I believe the answer is C) 02413 because the setTimeout with 0ms delay will be executed first.
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Doyle
3 months ago
I think the answer is B) 02431 because the setTimeout with 0ms delay will be executed last.
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