Okay, let's do this! I'm feeling confident with B) 02431. Those setTimeout's with a 0 millisecond delay always get executed after the current synchronous code. Gotta love JavaScript's quirks, am I right?
Haha, this one's a real brain-teaser! I'm gonna go with C) 02413 just to be different. Who knows, maybe the exam folks are trying to catch us out with a trick question.
Hmm, let's see... If I remember my JavaScript fundamentals, the console.log's will execute in the order they're written, and the setTimeout's will get added to the task queue. So the answer has to be B) 02431. I hope I'm right!
Yes, the setTimeout functions will be added to the task queue and executed after the initial console.log statements. B) 02431 looks like the correct sequence.
That makes sense, the setTimeout functions have a delay of 0 milliseconds, so they will be executed after the initial console.log statements. B) 02431 seems correct.
Yes, that's correct! The setTimeout functions will be executed after the initial console.log statements, following the order they were added to the task queue. So it's definitely B) 02431.
I think you're right, the setTimeout functions will be added to the task queue and executed after the console.log statements. So it should be B) 02431.
I think you're right, the setTimeout functions will be added to the task queue and executed after the initial console.log statements. So it should be B) 02431.
Ah, the classic event loop conundrum! I'm pretty sure the correct answer is B) 02431. Those setTimeout's can be tricky, but I think I've got the hang of it now.
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