OutSystems Exam Associate-Reactive-Developer Topic 1 Question 18 Discussion

Actual exam question for OutSystems's Associate-Reactive-Developer exam

Question #: 18
Topic #: 1

[All Associate-Reactive-Developer Questions]

Consider the following Action (https://drive.google.com/file/d/1L6qUwd2jjqWAluUB-Kv5gQghendWoMr2/view?usp=sharing), that calculates the square root (sqrt) of a positive decimal number (N). Knowing that the function was called with N = 0, and the debugger is stopped at the Start node, what will happen when the developer selects the Continue (F9) option highlighted in the picture?

AThe Action will end, with sqrt = 0.

BThe Action will throw an exception and sqrt will have no value.

CThe debugger will stop in the N < 0 If node.

DThe debugger will stop at the breakpoint in the End node.

Show Suggested Answer

Suggested Answer: C

by Ryan at Mar 09, 2024, 09:21 PM

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Susana

1 months ago

I'm going with option B - it's gotta throw an exception. I mean, come on, dividing by zero? That's like the first thing they teach you in programming 101. Although, I'd love to see the developer's face if the debugger just shrugged and stopped at the N < 0 node. That would be a real 'mic drop' moment.

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Demetra

21 days ago

I think it will throw an exception too. Dividing by zero is a big no-no.

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Chantell

1 months ago

Option D seems like the safest bet. The debugger will stop at the breakpoint in the End node, which is the responsible thing to do. But you know what they say, 'expect the unexpected' - maybe the action will just explode and leave the developer scratching their head.

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Malcom

12 days ago

Yeah, I agree. It's always good to be prepared for unexpected errors.

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Rosita

21 days ago

I think option D is the most likely outcome.

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Lisha

2 months ago

Hmm, I'm leaning towards option C. If N is 0, the debugger should stop at the N < 0 node, right? That's the logical choice. Although, I can't help but wonder if the developer secretly programmed in a surprise ending where the action just ends with sqrt = 0.

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Amie

17 days ago

Yeah, it makes sense considering N is 0. The developer probably set it up that way.

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Delbert

19 days ago

I agree, that seems like the logical outcome based on the information provided.

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Lisha

1 months ago

I think option C is the correct choice. The debugger will stop at the N < 0 If node.

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Jerlene

2 months ago

I think option B is the way to go. Dividing by zero is a big no-no, so it's gotta throw an exception. Although, it'd be pretty funny if the debugger just stopped at the N < 0 node instead. What is this, amateur hour?

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Marica

8 days ago

I think the debugger stopping at the N < 0 node would be a bit unexpected. But hey, anything can happen in coding, right?

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Yvonne

1 months ago

Yeah, throwing an exception makes sense. Can't have undefined values floating around.

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Wenona

1 months ago

Well, we'll have to wait and see. It could go either way.

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William

1 months ago

I'm not so sure, I think the debugger might just stop at the N < 0 node instead.

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Suzan

1 months ago

I agree, option B seems like the most logical choice. Dividing by zero is a definite no-go.

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Nell

2 months ago

Yeah, I think so too. It's a common mistake that would definitely throw an exception.

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Anglea

2 months ago

I agree, option B seems most likely. Dividing by zero is a definite exception.

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Shelton

2 months ago

Well, if N is 0, then the square root should be 0, so option A seems correct. But I wonder what happens if N is negative - will it throw an exception or just stop at the N < 0 node?

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