Oracle Exam 1Z0-808 Topic 10 Question 89 Discussion

Actual exam question for Oracle's 1Z0-808 exam

Question #: 89
Topic #: 10

[All 1Z0-808 Questions]

Given:

What is the result?

AmyStr: 7007, myNum: 7007

BError

CmyStr: 9009, myNum: 7007

DmyStr: 7007, myNum: 9009

Show Suggested Answer

Suggested Answer: C

by Gilma at Apr 12, 2024, 04:39 PM

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Dorinda

8 days ago

Wait, wait, wait... What if the question is actually testing our knowledge of the order of operations? Maybe the answer is D) true true. You know, like, (5 > 3) && (4 == 4).

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Lashawnda

10 days ago

I'm with Ollie and 2 on this one. C) true false is the way to go. The Java gods are not trying to trick us, we just need to apply the logical operator rules properly.

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Norah

11 days ago

Haha, Marquetta, you're overthinking it! The answer is clearly C. The short-circuit evaluation is the key here. No need to get all twisted up about it.

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Marquetta

12 days ago

Hmm, I'm not so sure. What if the question is trying to trick us? Maybe the answer is B) false true. I mean, the first part is false, and the second part is true, right? This could be a sneaky one.

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I agree with Ollie, the answer is C. The boolean expression (5 > 3 || 4 < 2) && (4 == 2) is evaluated left-to-right. The first part, (5 > 3 || 4 < 2), evaluates to true because 5 is greater than 3. The second part, (4 == 2), evaluates to false. So, the overall result is true false.

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Ollie

16 days ago

This question is a classic Java tricky question! It's designed to test our understanding of the short-circuit evaluation of logical operators. I think the answer is C) true false.

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Oracle Exam 1Z0-808 Topic 10 Question 89 Discussion

Contribute your Thoughts:

Dorinda

Lashawnda

Norah

Marquetta

Della

Ollie