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Oracle Exam 1Z0-829 Topic 9 Question 26 Discussion

Actual exam question for Oracle's 1Z0-829 exam
Question #: 26
Topic #: 9
[All 1Z0-829 Questions]

Given the code fragment:

Which action enables the code to compile?

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Suggested Answer: D

The code fragment compares four pairs of strings using the equals() and intern() methods. The equals() method compares the content of two strings, while the intern() method returns a canonical representation of a string, which means that it returns a reference to an existing string with the same content in the string pool. The string pool is a memory area where strings are stored and reused to save space and improve performance. The results of the comparisons are as follows:

s1.equals(s2): This returns true because both s1 and s2 have the same content, ''Hello Java 17''.

s1 == s2: This returns false because s1 and s2 are different objects with different references, even though they have the same content. The == operator compares the references of two objects, not their content.

s1.intern() == s2.intern(): This returns true because both s1.intern() and s2.intern() return a reference to the same string object in the string pool, which has the content ''Hello Java 17''. The intern() method ensures that there is only one copy of each distinct string value in the string pool.

''Hello Java 17'' == s2: This returns false because ''Hello Java 17'' is a string literal, which is automatically interned and stored in the string pool, while s2 is a string object created with the new operator, which is not interned by default and stored in the heap. Therefore, they have different references and are not equal using the == operator.


Contribute your Thoughts:

Tu
2 days ago
B) Remove the regNO initialization statement. Duh, it's the only option that actually addresses the compile error. Some of these answers are just plain silly.
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Bea
13 days ago
Haha, E) Make the regNo variable public? That's just asking for trouble! Encapsulation, people, encapsulation!
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Denae
10 hours ago
User1: A) Replace record with void.
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Novella
18 days ago
I think D) Replace the regNo variable with static is the way to go. Making it static will allow the variable to be accessed without creating an instance of the class.
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Celia
3 days ago
I think D) Replace the regNo variable with static is the way to go.
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Leonida
20 days ago
The correct answer is B) Remove the regNO initialization statement. The code snippet has a compile error because the record type does not have a default constructor, so initializing regNo within the declaration is not allowed.
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Holley
26 days ago
But making the variable static will allow it to be accessed without an instance of the class.
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Whitley
27 days ago
I disagree, I believe the answer is D) Replace the regNo variable static.
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Holley
28 days ago
I think the correct answer is C) Make the regNo variable static.
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