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Oracle Exam 1Z0-829 Topic 9 Question 17 Discussion

Actual exam question for Oracle's 1Z0-829 exam
Question #: 17
Topic #: 9
[All 1Z0-829 Questions]

Given the code fragment:

What is the result?

Show Suggested Answer Hide Answer
Suggested Answer: B

Contribute your Thoughts:

Fernanda
1 months ago
Wait, did you guys forget to carry the one? I'm pretty sure the answer is 'Woof Woof'.
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Carisa
4 days ago
No, I believe it is 'Cat'
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Corazon
18 days ago
I think the answer is 'Dog'
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Tijuana
1 months ago
Really? A NullPointerException? That's so last year. I'm going with option C. The output will be 'Dog Dog' because the first println() statement will print 'Dog' and the second one will also print 'Dog'.
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Kasandra
2 months ago
Haha, this is a tricky one! I'm leaning towards option D. The output will be 'Cat null' because the second println() statement will print 'null' since the variable 'dog' is not initialized.
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Meaghan
3 days ago
Yes, option D seems to be the right choice. 'Cat null' will be the output due to the uninitialized variable.
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Meaghan
4 days ago
I believe it will print 'Cat null' as well. The second println() will print null for the uninitialized variable.
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Meaghan
8 days ago
I think option D is correct too. The variable 'dog' is not initialized, so it will print null.
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Tracey
2 months ago
Hmm, I'm not so sure. I think a NullPointerException might be thrown since the second println() statement tries to access a null reference. I'll go with option B.
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Roosevelt
16 days ago
Yes, option B is the most likely outcome due to the null reference in the second println() statement.
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Keshia
1 months ago
I agree, NullPointerException might be thrown because of the null reference. Option B seems right.
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Garry
2 months ago
I think option B is correct. The second println() statement could cause a NullPointerException.
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Eliz
2 months ago
I'm going with option A. The output should be 'Cat Dog' because the first println() statement will print 'Cat' and the second one will print 'Dog'.
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Franklyn
18 days ago
I'm going with option D. The first println() will print 'Cat' and the second one will print 'null'.
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Ty
26 days ago
I'm not sure about that. I think it's option C. Both println() statements will print 'Dog'.
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Malissa
1 months ago
I disagree, I believe it's option B. A NullPointerException will be thrown and then 'Cat Cat' will be printed.
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Tequila
1 months ago
I think it's option A too. The first println() will print 'Cat' and the second one will print 'Dog'.
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Brande
2 months ago
I see your point, but I still think A) Cat Dog is correct because of the code logic.
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Jillian
3 months ago
I disagree, I believe the answer is B) A NullPointerException is thrown Cat Cat.
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Brande
3 months ago
I think the answer is A) Cat Dog.
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