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Oracle Exam 1Z0-829 Topic 10 Question 24 Discussion

Actual exam question for Oracle's 1Z0-829 exam
Question #: 24
Topic #: 10
[All 1Z0-829 Questions]

Given the code fragment:

What is the result?

Show Suggested Answer Hide Answer
Suggested Answer: D

The code fragment compares four pairs of strings using the equals() and intern() methods. The equals() method compares the content of two strings, while the intern() method returns a canonical representation of a string, which means that it returns a reference to an existing string with the same content in the string pool. The string pool is a memory area where strings are stored and reused to save space and improve performance. The results of the comparisons are as follows:

s1.equals(s2): This returns true because both s1 and s2 have the same content, ''Hello Java 17''.

s1 == s2: This returns false because s1 and s2 are different objects with different references, even though they have the same content. The == operator compares the references of two objects, not their content.

s1.intern() == s2.intern(): This returns true because both s1.intern() and s2.intern() return a reference to the same string object in the string pool, which has the content ''Hello Java 17''. The intern() method ensures that there is only one copy of each distinct string value in the string pool.

''Hello Java 17'' == s2: This returns false because ''Hello Java 17'' is a string literal, which is automatically interned and stored in the string pool, while s2 is a string object created with the new operator, which is not interned by default and stored in the heap. Therefore, they have different references and are not equal using the == operator.


Contribute your Thoughts:

Louis
2 months ago
Is this a cat-astrophe or a dog-ma? I'm just gonna roll with option C and say 'Dog Dog' - at least that's not a complete mess!
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Barrett
2 months ago
Wait, is this a trick question? I'm gonna go with option B. Throwing a NullPointerException sounds like the kind of thing the exam would do to mess with us.
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Leonie
6 days ago
I agree with you, option B does seem like a possibility for this code fragment.
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Casandra
7 days ago
I'm not so sure, I think option A might be the correct result.
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Dino
1 months ago
I think you might be right, option B does seem like a tricky answer.
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Cordell
2 months ago
Haha, this question is a piece of cake! I'm going with option A. Who needs 'null' when you've got 'Cat' and 'Dog'?
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Caprice
10 days ago
Yeah, option A is the way to go for sure.
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Ryan
11 days ago
I'm going with option A as well, it's the obvious choice.
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Cruz
15 days ago
I think so too, 'Cat' and 'Dog' are definitely better than 'null'.
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Brandon
18 days ago
I agree, option A seems like the correct choice.
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Myong
21 days ago
I think I'll go with option B. 'Cat' and 'null' might be the result.
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Lonny
27 days ago
I agree, option A is the way to go. 'Cat' and 'Dog' all the way!
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Charlette
2 months ago
I think option A is the correct answer. The code looks pretty straightforward, and the output should be 'Cat Dog'.
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Ellen
3 months ago
The output will be 'Cat Dog' as per the given code. The 'cat' object is not null, so it will print 'Cat' and the 'dog' object is also not null, so it will print 'Dog'.
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Ashley
2 months ago
Dog
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Margart
2 months ago
A) Cat
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Bernadine
3 months ago
I'm not sure, but I think the answer might be D) Cat null.
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Avery
3 months ago
I agree with Jessenia, because the code is trying to access a null object.
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Jessenia
3 months ago
I think the answer is B) A NullPointerException is thrown Cat Cat.
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