Oracle Exam 1Z0-819 Topic 8 Question 37 Discussion

Actual exam question for Oracle's 1Z0-819 exam

Question #: 37
Topic #: 8

[All 1Z0-819 Questions]

Given:

List longlist = List.of(''Hello'',''World'',''Beat'');

List shortlist = new ArrayList<>();

Which code fragment correctly forms a short list of words containing the letter ''e''?

AOption A

BOption B

COption C

DOption D

Show Suggested Answer

Suggested Answer: A

-jdkinternals option analyzes all classes in the .jar for class-level dependencies on JDK internal APIs. If any are found, the results with suggested replacements are output in the console.

by Alyce at May 03, 2022, 10:13 AM

Limited Time Offer

25%

Off

Get Premium 1Z0-819 Questions as Interactive Web-Based Practice Test or PDF

Contribute your Thoughts:

Submit Cancel

Helga

2 months ago

I'm going with Option C. It's the only one that doesn't make me scratch my head and go, 'Huh?'

upvoted 0 times

Jules

25 days ago

User3: Option D seems like the best choice to me.

upvoted 0 times

...

Marya

1 months ago

User2: I'm going with Option C. It's the only one that doesn't make me scratch my head and go, 'Huh?'

upvoted 0 times

...

Samira

1 months ago

User1: I think Option A is the correct one.

upvoted 0 times

...

Farrah

2 months ago

Option C is the way to go! It's the only one that actually makes sense. The other options are like trying to find a needle in a haystack with a blindfold on.

upvoted 0 times

...

Adell

2 months ago

Hmm, I'm leaning towards Option C as well. It's the only one that specifically checks for the 'e' character in each string.

upvoted 0 times

Tammara

2 hours ago

Let's go with Option C then.

upvoted 0 times

...

Sanda

9 days ago

Option C is the one that filters out words without the letter 'e'.

upvoted 0 times

...

Justa

14 days ago

I agree, Option C looks like the right choice.

upvoted 0 times

...

Alida

1 months ago

I think Option C is the correct one.

upvoted 0 times

...

Nguyet

2 months ago

I'm not sure about this one. Option A seems a bit too simple, and Options B and D don't seem to address the requirement of finding words with the letter 'e'.

upvoted 0 times

...

Kris

2 months ago

Oh, I think Option C looks like the correct answer. It iterates through the 'longlist' and adds any strings containing the letter 'e' to the 'shortlist'.

upvoted 0 times