Oracle Exam 1Z0-809 Topic 9 Question 70 Discussion

Actual exam question for Oracle's 1Z0-809 exam

Question #: 70
Topic #: 9

[All 1Z0-809 Questions]

Given the code fragment:

Which modification enables the code to print Price 5 New Price 4?

AReplace line n2 with .map (n -> System.out.println (''New Price'' + n --1)) and remove line n3

BReplace line n2 with .mapToInt (n -> n -- 1);

CReplace line n1 with .forEach (e -> System.out.print (''Price'' + e))

DReplace line n3 with .forEach (n -> System.out.println (''New Price'' + n));

Show Suggested Answer

Suggested Answer: D

by Avery at Aug 28, 2024, 12:45 PM

Limited Time Offer

25%

Off

Get Premium 1Z0-809 Questions as Interactive Web-Based Practice Test or PDF

Contribute your Thoughts:

Submit Cancel

Cherelle

9 months ago

I'm going with option A. Replacing line n2 with .map (n -> System.out.println (''New Price'' + n --1)) and removing line n3 should do the trick.

upvoted 0 times

Tamera

8 months ago

I'm not sure, but I would go with option B.

upvoted 0 times

...

Silva

8 months ago

I disagree, I believe option D is the right choice.

upvoted 0 times

...

Merlyn

8 months ago

I think option A is the correct one.

upvoted 0 times

...

Steffanie

9 months ago

Haha, I bet the real answer is to just add a '+' to the 'New Price' string! Developers love their shortcuts.

upvoted 0 times

Devorah

8 months ago

Haha, I bet the real answer is to just add a '+' to the 'New Price' string! Developers love their shortcuts.

upvoted 0 times

...

Ayesha

9 months ago

Maybe it's B) Replace line n2 with .mapToInt (n -> n -- 1);

upvoted 0 times

...

Vince

9 months ago

No, I believe it's A) Replace line n2 with .map (n -> System.out.println ('New Price' + n --1)) and remove line n3

upvoted 0 times

...

Nichelle

9 months ago

I think the answer is D) Replace line n3 with .forEach (n -> System.out.println ('New Price' + n));

upvoted 0 times

...

Elouise

9 months ago

I see your point, Hubert. I think you're right. The answer is D.

upvoted 0 times

...

Hubert

9 months ago

But if you replace line n3 with .forEach (n -> System.out.println (''New Price'' + n)), it will print Price 5 New Price 4.

upvoted 0 times

...

Erick

9 months ago

Option D seems more straightforward to me. Replacing line n3 with .forEach (n -> System.out.println (''New Price'' + n)) will directly print the new price.

upvoted 0 times

...

Lorrie

10 months ago

I think option B is the correct answer. Replacing line n2 with .mapToInt (n -> n -- 1) will decrement each value by 1 and print the new price.

upvoted 0 times

Bernadine

9 months ago

Yes, I think so too. It makes sense to decrement each value by 1 to get the new price.

upvoted 0 times

...

Nakita

9 months ago

I agree with you, option B seems like the correct choice.

upvoted 0 times

...

Blondell

10 months ago

I disagree, I believe the answer is A.

upvoted 0 times

...

Hubert

10 months ago

I think the answer is D.

upvoted 0 times

...