Oracle Exam 1Z0-809 Topic 8 Question 60 Discussion

Actual exam question for Oracle's 1Z0-809 exam

Question #: 60
Topic #: 8

[All 1Z0-809 Questions]

Given the code fragment:

List nL = Arrays.asList(''Jim'', ''John'', ''Jeff'');

Function funVal = s -> ''Hello : ''.contact(s);

nL.Stream()

.map(funVal)

.peek(System.out::print);

What is the result?

AHello : Jim Hello : John Hello : Jeff

BJim John Jeff

CThe program prints nothing.

DA compilation error occurs.

Show Suggested Answer

Suggested Answer: D

by Maybelle at Apr 24, 2024, 08:16 AM

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Muriel

1 months ago

I'm just hoping the exam doesn't ask us to write any code with lambdas. That's the real challenge here.

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Annelle

1 months ago

Ah, the good old days when we had to type out 'new ArrayList()' instead of this fancy 'Arrays.asList()' business. Kids these days have it easy!

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Penney

2 days ago

B) Jim John Jeff

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Honey

4 days ago

B) Jim John Jeff

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Penney

11 days ago

A) Hello : Jim Hello : John Hello : Jeff

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Honey

18 days ago

A) Hello : Jim Hello : John Hello : Jeff

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Celestine

1 months ago

I'm feeling a little hungry. Maybe I should've had a snack before this exam. Oh, and I'm pretty sure the answer is A.

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Christa

2 months ago

Ah, I see what's going on here. The stream is being processed, but the results aren't being collected anywhere. Option C might be the winner.

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Izetta

6 days ago

Looks like we're all in agreement. Option C it is.

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Izetta

9 days ago

I think so too. The program doesn't seem to be collecting the results anywhere.

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Izetta

26 days ago

Yes, you're right. Option C seems to be the most likely outcome.

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Orville

2 months ago

Wait, what's this 'contact' method? Shouldn't it be 'concat'? I'm going to have to double-check that.

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Lamar

19 days ago

User3: Yeah, I agree. It should be 'concat'.

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Susy

21 days ago

User2: A) Hello : Jim Hello : John Hello : Jeff

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Tesha

26 days ago

User1: I think it's supposed to be 'concat' not 'contact'.

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Christiane

2 months ago

Hmm, the stream processing looks pretty straightforward. I think I'll go with option A.

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Norah

1 months ago

Yes, the stream processing will print Hello : Jim Hello : John Hello : Jeff.

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Jade

2 months ago

I agree, option A seems correct.

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Carylon

3 months ago

I'm not sure, but I think the answer might be D) A compilation error occurs because there is a syntax error in the code fragment.

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Stephaine

3 months ago

I agree with Rolande, because the code fragment uses map and peek functions to apply the funVal function to each element in the stream.

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Rolande

3 months ago

I think the answer is A) Hello : Jim Hello : John Hello : Jeff

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