Oracle Exam 1Z0-809 Topic 16 Question 61 Discussion

Actual exam question for Oracle's 1Z0-809 exam

Question #: 61
Topic #: 16

[All 1Z0-809 Questions]

Given:

IntStream stream = IntStream.of (1,2,3);

IntFunction inFu= x -> y -> x*y;//line n1

IntStream newStream = stream.map(inFu.apply(10));//line n2

newStream.forEach(System.out::print);

Which modification enables the code fragment to compile?

AReplace line n1 with:IntFunction<UnaryOperator> inFu = x -> y -> x*y;

BReplace line n1 with:IntFunction<IntUnaryOperator> inFu = x -> y -> x*y;

CReplace line n1 with:BiFunction<IntUnaryOperator> inFu = x -> y -> x*y;

DReplace line n2 with:IntStream newStream = stream.map(inFu.applyAsInt (10));

Show Suggested Answer

Suggested Answer: D

by Lashawna at Apr 30, 2024, 02:02 PM

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Jame

1 months ago

D is the way to go. Gotta love those functional interfaces and their specific method names. Makes total sense to use applyAsInt() here.

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Rusty

1 months ago

Haha, C is definitely not the right answer. A BiFunction with an IntUnaryOperator? That doesn't even make sense!

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Mabelle

1 months ago

I think B is the right answer. The IntFunction needs to take an IntUnaryOperator, which is a functional interface that takes an int and returns an int.

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Launa

1 days ago

B) Replace line n1 with:IntFunction inFu = x -> y -> x*y;

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Donette

3 days ago

A) Replace line n1 with:IntFunction inFu = x -> y -> x*y;

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3 months ago

I think the correct answer is B.

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