Oracle Exam 1Z0-809 Topic 14 Question 85 Discussion

Actual exam question for Oracle's 1Z0-809 exam

Question #: 85
Topic #: 14

[All 1Z0-809 Questions]

Given the code fragment:

UnaryOperator uo1 = s -> s*2;line n1

List loanValues = Arrays.asList(1000.0, 2000.0);

loanValues.stream()

.filter(lv -> lv >= 1500)

.map(lv -> uo1.apply(lv))

.forEach(s -> System.out.print(s + '' ''));

What is the result?

A4000.0

B4000

CA compilation error occurs at line n1.

DA compilation error occurs at line n2.

Show Suggested Answer

Suggested Answer: D

by Jerrod at Apr 06, 2025, 01:24 AM

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Lucina

2 months ago

I'm going with A. The stream will filter out the values less than 1500, then double the remaining values.

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Miss

16 days ago

C) A compilation error occurs at line n1.

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Lavera

17 days ago

I think it will be B) 4000

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Glenna

25 days ago

A) 4000.0

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Keva

2 months ago

I'm not sure, but I think there might be a compilation error at line n1

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Coleen

2 months ago

I agree with Celestina, the code should multiply by 2 and print the result

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Larue

2 months ago

Ha! I bet someone will say the answer is 'A compilation error occurs' just to be tricky.

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Gregg

7 days ago

User3

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Izetta

10 days ago

User2

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Zona

12 days ago

User1

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Chun

2 months ago

The key is understanding the UnaryOperator type. It's going to apply the lambda function to each element in the stream, doubling the value.

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Celestina

2 months ago

I think the result will be 4000.0

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Wai

2 months ago

Hmm, the question seems straightforward. I think the answer is A) 4000.0.

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Andra

1 months ago

I think so too, it should be A) 4000.0.

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Andra

1 months ago

I agree, the answer is A) 4000.0.

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Cammy

1 months ago

Great, we all agree on A) 4000.0 as the answer.

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Argelia

1 months ago

Yes, the correct answer is A) 4000.0.

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Huey

2 months ago

I think so too, it should be A) 4000.0.

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Irma

2 months ago

I agree, the answer is A) 4000.0.

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