Oracle Exam 1Z0-809 Topic 1 Question 32 Discussion

Actual exam question for Oracle's 1Z0-809 exam

Question #: 32
Topic #: 1

[All 1Z0-809 Questions]

Given the code fragment:

List codes = Arrays.asList (10, 20);

UnaryOperator uo = s -> s +10.0;

codes.replaceAll(uo);

codes.forEach(c -> System.out.println(c));

What is the result?

A20.030.0

B1020

CA compilation error occurs.

DA NumberFormatException is thrown at run time.

Show Suggested Answer

Suggested Answer: D

by Rasheeda at Aug 25, 2022, 03:52 AM

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Adaline

7 days ago

Haha, I'm going with C) A compilation error occurs. The code looks like it's written in some alien language, so it's bound to have issues compiling.

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Evangelina

8 days ago

I think the answer is B) 1020. The replaceAll method modifies the list in-place, so the original integer values are still present.

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Erick

21 days ago

The correct answer is A) 20.0 30.0. The UnaryOperator uo is applied to each element in the list, adding 10.0 to each value.

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Yoko

4 days ago

A) 20.0 30.0

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Malinda

24 days ago

I agree with Osvaldo, because the UnaryOperator cannot be applied to List.

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Osvaldo

25 days ago

I believe the answer is C) A compilation error occurs.

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Melvin

1 months ago

I think the result will be 20.0 and 30.0.

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