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Oracle Exam 1Z0-808 Topic 10 Question 89 Discussion

Actual exam question for Oracle's 1Z0-808 exam
Question #: 89
Topic #: 10
[All 1Z0-808 Questions]

Given:

What is the result?

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Suggested Answer: C

by Gilma at Apr 12, 2024, 04:39 PM

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Diane
12 months ago
I disagree, I believe the correct answer is B) false true.
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Kathryn
12 months ago
I'm not sure, but I think it could also be D) true true.
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Gerald
1 years ago
I agree with the code will output true false.
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Cordelia
1 years ago
I think the result is C) true false.
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Dorinda
1 years ago
Wait, wait, wait... What if the question is actually testing our knowledge of the order of operations? Maybe the answer is D) true true. You know, like, (5 > 3) && (4 == 4).
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Lashawnda
1 years ago
I'm with Ollie and 2 on this one. C) true false is the way to go. The Java gods are not trying to trick us, we just need to apply the logical operator rules properly.
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Norah
1 years ago
Haha, Marquetta, you're overthinking it! The answer is clearly C. The short-circuit evaluation is the key here. No need to get all twisted up about it.
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Marquetta
1 years ago
Hmm, I'm not so sure. What if the question is trying to trick us? Maybe the answer is B) false true. I mean, the first part is false, and the second part is true, right? This could be a sneaky one.
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Della
1 years ago
I agree with Ollie, the answer is C. The boolean expression (5 > 3 || 4 < 2) && (4 == 2) is evaluated left-to-right. The first part, (5 > 3 || 4 < 2), evaluates to true because 5 is greater than 3. The second part, (4 == 2), evaluates to false. So, the overall result is true false.
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Narcisa
11 months ago
Agreed. C) true false.
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Johnna
11 months ago
Yes, I agree. Let's go with C.
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Shannon
12 months ago
I think the answer is C.
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Ollie
1 years ago
This question is a classic Java tricky question! It's designed to test our understanding of the short-circuit evaluation of logical operators. I think the answer is C) true false.
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