Oracle Exam 1Z0-533 Topic 3 Question 59 Discussion

Actual exam question for Oracle's 1Z0-533 exam

Question #: 59
Topic #: 3

[All 1Z0-533 Questions]

Given the following:

Measures (Dense): 40 stored members, 50 total members Time (Dense): 17 stored members, 17

total members Scenario (Dense): 2 stored members, 5 total members Market (Sparse): 100 stored

members, 100 total members Product(Sparse): 500 stored members, 550 total members

What is the block size in bytes?

ABlock size = 40 * 17 * 2

BBlock size = 40 * 17 * 2 * 8

CBlock size = 50 * 17 * 5 * 8

DBlock size = 50 * 17 * 5

EBlock size = 100 * 500 * 8

FBlock size = 100 * 500

Show Suggested Answer

Suggested Answer: C

by Norah at Feb 09, 2024, 08:05 PM

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Aleshia

12 months ago

Yes, I agree with that reasoning. The block size should be 40 * 17 * 2 * 8.

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Raul

12 months ago

That makes sense. So the answer would be Block size = 40 * 17 * 2 * 8.

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Shayne

12 months ago

I believe the correct formula should include multiplying by 8 to convert to bytes.

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Carlton

12 months ago

So, for the Measures dimension, the calculation would be 40 * 17 * 2.

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Aleshia

12 months ago

I agree. We need to consider both the stored and total members for each dimension.

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Raul

1 years ago

I think the block size should be calculated using the number of stored members and total members.

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Alison

1 years ago

I see your point, Mireya. Maybe we should revisit the formulas and calculations to ensure accuracy.

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Mireya

1 years ago

That makes sense, Vanna. The block size should take into account the total members for each dimension.

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Vanna

1 years ago

I disagree with Alison. I think the block size should be calculated differently, maybe Block size = 50 * 17 * 5.

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Alison

1 years ago

I believe the correct formula to calculate the block size is Block size = 40 * 17 * 2 * 8.

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Mireya

1 years ago

I think the block size should be calculated based on the measures and time stored members.

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