Ah, the old 'trick question' strikes again! But I think I've got it figured out. Option A is the way to go - the maximum salary employees will be first in descending order, and the rest will follow suit. *winks* Gotta love these SQL puzzles, don't you?
I'm going to have to go with option A on this one. The CASE statement is clearly designed to prioritize the employees with the maximum salary, and the DESC keyword at the end seals the deal. *chuckles* I wonder if the exam writer was feeling a bit mischievous with this one.
This is a tricky one! I can see how the CASE statement could be interpreted in different ways, but I'm leaning towards option A. Sorting the maximum salary employees first in descending order makes the most sense to me.
Hmm, I'm not so sure about this one. The CASE statement seems a bit convoluted, but I think the employees with the maximum salary will appear first in descending order. Let me double-check the options.
The statement is definitely selecting the employees with the maximum salary and sorting them in descending order. The rest of the employees will be sorted by their last name in descending order as well. Option A is the correct answer.
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