Huawei Exam H35-560 Topic 4 Question 80 Discussion

Actual exam question for Huawei's H35-560 exam

Question #: 80
Topic #: 4

[All H35-560 Questions]

The insertion loss of the cavity power divider is larger than that of the microstrip power divider.

ATrue

BFalse

Show Suggested Answer

Suggested Answer: B

by Leoma at Mar 06, 2025, 07:47 AM

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Clay

2 months ago

B) False, for sure. Cavity power dividers are the way to go if you want less insertion loss. Microstrip power dividers? More like 'micro-loss'! *chuckles*

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Barbra

29 days ago

B) False

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Brittni

1 months ago

A) True

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Wei

1 months ago

B) False

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Allene

2 months ago

A) True

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Stephaine

2 months ago

So the statement is true then, the insertion loss of the cavity power divider is larger.

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Franchesca

2 months ago

Hmm, I'm not too sure about this one. But I'll go with B) False just to be safe. Gotta love these tricky power divider questions!

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Catina

2 months ago

That's true, but in this case, the cavity power divider has more loss.

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Domitila

2 months ago

But isn't the microstrip power divider known for its lower insertion loss?

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Stephaine

2 months ago

I agree with Catina, the cavity power divider usually has more loss.

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Susy

2 months ago

Cavity power dividers are more efficient, so B) False is the correct answer here.

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Elouise

1 months ago

So, the correct answer is B) False because cavity power dividers are more efficient.

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Elly

1 months ago

I agree, the insertion loss of the cavity power divider is actually smaller than that of the microstrip power divider.

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Anthony

2 months ago

I think the cavity power divider is more efficient, so the answer is B) False.

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Catina

3 months ago

I think the insertion loss of the cavity power divider is larger.

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Jutta

3 months ago

I think the answer is B) False. The microstrip power divider typically has higher insertion loss compared to the cavity power divider.

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Sage

3 months ago

I agree, the cavity power divider usually has higher insertion loss than the microstrip power divider.

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Lucille

3 months ago

A) True

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