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F5 Networks Exam 301a Topic 1 Question 101 Discussion

Actual exam question for F5 Networks's 301a exam
Question #: 101
Topic #: 1
[All 301a Questions]

Refer to the Exhibit.

An LTM Specialist notices that two members in a pool are overloaded. To relive the existing members a fourth member (10.128.20.14) is brought up.

How many member will receive and process new connections?

Show Suggested Answer Hide Answer
Suggested Answer: D

Contribute your Thoughts:

Natalie
1 months ago
Haha, trick question! The new member is obviously there to look pretty, not actually process any connections. I'm picking D, just to be safe.
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Alberto
4 days ago
I'm not so sure, I think the new member is just there for show. I'm sticking with D.
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Danica
9 days ago
I agree, I also think the new member is there to help process connections. A sounds like the right choice.
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Ben
12 days ago
I think the new member is there to help process connections, so I'm going with A.
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Stephen
2 months ago
This is a tricky one. I'm going to assume the new member is added to the load-balancing pool, so all four members will share the new connections. Gotta go with A on this one.
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Paris
11 days ago
Great, we're all on the same page then. A) 4 it is.
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Rodolfo
28 days ago
Yes, that makes sense. So, the answer is A) 4.
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Linn
1 months ago
I agree, adding the new member to the pool should distribute the new connections among all four members.
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Marjory
2 months ago
Wait, I thought the question said to relieve the existing members. Wouldn't that mean the new member would take on the load, leaving the other three to handle the new connections? C looks like the right answer to me.
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Clemencia
24 days ago
C) 2
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Angelica
28 days ago
B) 3
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Makeda
1 months ago
A) 4
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Herman
2 months ago
Hmm, let's see. If we have two overloaded members and a new one is brought up, that should distribute the load across all four members, right? I'm going with option A.
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Beth
1 months ago
Yes, with four members, each should receive and process new connections.
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Ceola
2 months ago
I agree, adding a fourth member should distribute the load evenly.
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Kristeen
2 months ago
I'm not sure, but I think the answer is A) 4 as well. It makes sense to have all four members processing new connections.
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Theron
2 months ago
I agree with Keena, because the fourth member was brought up to relieve the overloaded members.
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Keena
3 months ago
I think the answer is A) 4.
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