F5 Networks Exam 201 Topic 1 Question 65 Discussion

Actual exam question for F5 Networks's 201 exam

Question #: 65
Topic #: 1

[All 201 Questions]

An LTM device has a virtual server mapped to www5f.com with a pool assigned. The objects are defined

as follows:

Virtual server. Destination 192.168.245.100.443 netmask 255.255.255.0

Persistence: Source address persistence netmask 255.0.0.0

SNAT:AutoMap

Profiles: HnP/TCP

How should the BIG-IP Administrator modify the persistence profile so that each unique IP address

creates a persistence record?

Anetmask 0.0.0.0

Bnetmask 255.255.255.255

Cnetmask 255.255.0.0

Dnetmask 255.256.255.0

Show Suggested Answer

Suggested Answer: C

by Tasia at Feb 05, 2023, 04:23 PM

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Blondell

2 months ago

I'm going to go with B) netmask 255.255.255.255. It seems like the most logical choice to create a unique persistence record for each IP address.

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Blossom

16 days ago

User3: Yes, I also believe that option B) is the right one to create a unique persistence record for each IP address.

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Lili

24 days ago

User2: I agree, that option seems to be the most logical for this scenario.

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Jamal

1 months ago

User1: I think B) netmask 255.255.255.255 is the correct choice for unique persistence records.

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Danilo

2 months ago

Haha, D) netmask 255.256.255.0? That's a pretty funny answer option. I'm pretty sure that's not a valid netmask.

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Nelida

2 months ago

Hmm, this question seems a bit tricky. I'm not sure if B) is the right answer. Maybe I should double-check the details of the LTM device and the persistence profile.

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Denna

19 hours ago

User3: I believe the answer is B) netmask 255.255.255.255

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Reita

16 days ago

User1: I think the correct answer is A) netmask 0.0.0.0

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Hoa

19 days ago

User2: I'm not so sure, maybe we should review the details again.

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Lashaunda

23 days ago

User1: I think the correct answer is A) netmask 0.0.0.0

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Altha

2 months ago

I think the answer is B) netmask 255.255.255.255. This will create a unique persistence record for each unique IP address, which is what the question is asking for.

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