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Cisco Exam 500-445 Topic 4 Question 9 Discussion

Actual exam question for Cisco's 500-445 exam
Question #: 9
Topic #: 4
[All 500-445 Questions]

What is the formula for a standardized agent count for email?

Show Suggested Answer Hide Answer
Suggested Answer: A

Contribute your Thoughts:

Letha
2 months ago
If they really wanted us to memorize this formula, they should have made it a song. I can't remember anything unless it has a catchy tune.
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Sylvia
2 months ago
Hmm, I'm torn between B and C. Maybe I should just flip a coin, that's how I usually pass these exams anyway.
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Tawna
21 days ago
Just flip a coin, that's what I do when I can't decide.
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Gilma
22 days ago
I would go with C) Standardized agent count for email = Actual agent count * Average number of messages handled per hour by each agent / 20
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Mohammad
1 months ago
I think the formula is B) Standardized agent count for email = Actual agent count * Average number of messages handled per hour by each agent / 6
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Deonna
2 months ago
D seems too simple, like they're just trying to trick us. I'm going with B, it has a better ring to it.
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My
2 months ago
I agree with you, I'm going with B.
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Lavonna
2 months ago
I think D is the correct formula.
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Stephania
2 months ago
I think the correct formula is B. It just makes more sense to divide the actual agent count by 6 to get the standardized count.
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Wilda
1 months ago
I agree with you, B seems like the right choice.
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Devorah
1 months ago
I'm pretty sure it's D.
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Junita
2 months ago
I think it's C actually.
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Annita
2 months ago
I believe the formula is A.
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Peter
3 months ago
But wouldn't it make more sense to divide by 10 instead of 4?
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Solange
3 months ago
I believe it's D.
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Peter
3 months ago
I think the formula is A.
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