C++ Institute Exam CPA Topic 8 Question 90 Discussion

Actual exam question for C++ Institute's CPA exam

Question #: 90
Topic #: 8

[All CPA Questions]

What will happen when you attempt to compile and run the following code?

#include

using namespace std;

int main (int argc, const char * argv[])

{

enum state { ok, error, warning};

enum state s1, s2, s3;

s1 = ok;

s2 = warning;

s3 = error;

s4 = ok;

cout << s1<< s2<< s3;

return 0;

}

AIt will print:''123''

Bcompilation error

CIt will print:''021''

DIt will print:''132''

Show Suggested Answer

Suggested Answer: B

by Tammara at Jun 23, 2024, 09:40 AM

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Phuong

10 months ago

Haha, this code is like a bad joke. Of course it's going to be a compilation error. Who writes code like that? B all the way!

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Hayley

10 months ago

Wow, this is a tricky one! I'm going to have to go with B. Compilation error. Can't use an undeclared variable like that and expect it to work.

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Candida

10 months ago

No, I believe it will result in a compilation error.

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Lemuel

10 months ago

I think it will print '123'.

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Laticia

11 months ago

I'm going with D. It will print '132'. The enum values are 0, 1, and 2, and we're printing them in the order s1, s2, s3, which should give us '132'.

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Bernardine

11 months ago

My guess is C. It will print '021'. The enum values are 0, 1, and 2, so when we print them, we should get that output.

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Truman

10 months ago

No, it will actually print '123'.

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Truman

10 months ago

I think it will print '021' as well.

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Stevie

11 months ago

I think it will print '132'.

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Broderick

11 months ago

I think it will print '021'.

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Sarah

11 months ago

I believe it will result in a compilation error.

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Tawna

11 months ago

Hmm, I think the answer is B. Compilation error. The code tries to use an undeclared variable s4, which should result in a compilation error.

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Mona

10 months ago

Yes, the code will give a compilation error due to the use of the undeclared variable s4.

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Solange

11 months ago

I agree, the code will not compile because of the undeclared variable s4.

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Ines

11 months ago

You're right, the answer is B. Compilation error because of the undeclared variable s4.

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Bea

11 months ago

Yes, the code will give a compilation error due to the use of the undeclared variable s4.

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Tatum

11 months ago

I agree, the code will not compile because of the undeclared variable s4.

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Theron

11 months ago

I think it will print '123'.

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