C++ Institute Exam CPA-21-02 Topic 7 Question 38 Discussion

Actual exam question for C++ Institute's CPA-21-02 exam

Question #: 38
Topic #: 7

[All CPA-21-02 Questions]

What happens when you attempt to compile and run the following code?

#include

using namespace std;

class A {

int x;

protected:

int y;

public:

int z;

A() { x=1; y=2; z=3; }

};

class B : public A {

string z;

public:

void set() {

y = 4;

z = "John";

}

void Print() {

cout << y << z;

}

};

int main () {

B b;

b.set();

b.Print();

return 0;

}

AIt prints: 4John

BIt prints: 2John

CIt prints: 23

DIt prints: 43

Show Suggested Answer

Suggested Answer: A

by My at Apr 07, 2025, 03:32 AM

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India

6 days ago

Hmm, I think the answer is B. The protected member `y` is accessible in the derived class `B`, so it will print 4John.

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Eleni

16 days ago

But doesn't the set() function in class B change the value of y to 4 before printing?

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Reynalda

20 days ago

I disagree, I believe the answer is B) It prints: 2John.

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Eleni

21 days ago

I think the answer is A) It prints: 4John.

upvoted 0 times

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