C++ Institute Exam CPA-21-02 Topic 1 Question 18 Discussion

Actual exam question for C++ Institute's CPA-21-02 exam

Question #: 18
Topic #: 1

[All CPA-21-02 Questions]

What happens when you attempt to compile and run the following code?

#include

using namespace std;

int main()

{

int *t;

t = new int[2];

for (int i=0; i<2; i++) {

t[i] = i;

}

cout << t[1];

}

AIt prints: 0

BIt prints: 1

CIt prints: 10

DIt prints: ?1

Show Suggested Answer

Suggested Answer: A, B

by Ena at Jun 22, 2024, 01:29 PM

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Georgene

2 months ago

This code is like a puzzle, but the solution is just a click away. I'm going to use my trusty debugger to figure this out.

upvoted 0 times

Helga

4 days ago

User 3: It prints: 1

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Leigha

5 days ago

User 2: I believe it prints: 1

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Kristian

15 days ago

User 1: I think it prints: 1

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Grover

2 months ago

Wait, did we forget to free the memory we allocated? I hope the examiner doesn't deduct points for that. Memory leaks are the bane of every programmer's existence.

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Francene

2 months ago

Haha, I bet the person who wrote this question is a real sadist. They're probably sitting back and laughing as they watch us struggle with this one.

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Remedios

2 months ago

Wow, this is a classic pointer question! I remember struggling with these in my exam. Good thing I brushed up on my dynamic memory allocation before taking this test.

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Janessa

9 days ago

User 3: I see, so the output is 1 because arrays are zero-indexed. The element at index 1 is the second element, which has a value of 1.

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Stanton

1 months ago

User 2: That's correct! The code allocates memory for an array of 2 integers and assigns values 0 and 1 to the elements. Then it prints the value at index 1, which is 1.

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Tamekia

1 months ago

User 1: It prints: 1

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Serina

2 months ago

The correct answer is B) It prints: 1. The code dynamically allocates an array of two integers and initializes them with 0 and 1 respectively. Then it prints the value at index 1, which is 1.

upvoted 0 times