Wait, isn't a full-factorial design the one where you test every possible combination? That sounds like a lot of work - I'll stick to my 2^k designs, thank you very much!
I'm not sure, but I think the answer might be D) 12 because each factor at two levels means 2^3 = 8 runs, and then we need to include all possible combinations, which would be 8 + 4 = 12.
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