AMA Exam PCM Topic 4 Question 68 Discussion

Actual exam question for AMA's PCM exam

Question #: 68
Topic #: 4

[All PCM Questions]

Resolve surveys 20,000 households that own a TV. The results of this survey indicate that an advertisement for a retail store was watched 360,000 times during a period of three days. The same advertisement was watched at least once by 30,000 people. What is the average frequency of the advertisement?

A30,000

B360,000

C12

D10,000

E1.5

Show Suggested Answer

Suggested Answer: C

by Blair at Apr 03, 2023, 08:14 PM

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Tran

6 days ago

D) 10,000 seems like the correct answer to me. The survey covered 20,000 households, so the average frequency would be 360,000 / 20,000 = 10,000 views.

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Rosann

9 days ago

I'm not sure, but I think the average frequency is calculated by dividing total views by total viewers, so it should be C) 12.

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Stevie

10 days ago

I agree with Isaiah, because the advertisement was watched 360,000 times by 30,000 people.

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Graham

18 days ago

I think the answer is C) 12. If 30,000 people watched the ad at least once, and the total number of views was 360,000, then the average frequency of the ad must be 12 views per person.

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Isaiah

19 days ago

I think the answer is C) 12.

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