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Adobe Exam AD0-E720 Topic 4 Question 15 Discussion

Actual exam question for Adobe's AD0-E720 exam
Question #: 15
Topic #: 4
[All AD0-E720 Questions]

An Adobe Commerce developer needs to display a URL in the template. How would the variable $ur1 be securely output in the template?

Show Suggested Answer Hide Answer
Suggested Answer: A, C

To apply a knockout binding to a

to run a function, onClick(), when it's clicked, the developer can use either of the following solutions:

A)

: This solution will use the click binding to execute the onClick() function as an expression when the
is clicked. The function will be called with the current binding context as the first parameter and the event object as the second parameter.

C)

: This solution will use the click binding to execute the onClick function as a reference when the
is clicked. The function will be called with the current binding context as the first parameter and the event object as the second parameter.

The following solutions are not valid and will not work:

B)

<!-- ko click: 'onClick' --><!-- /ko -->
: This solution will use the virtual element syntax to apply the click binding, but it will pass a string literal instead of a function expression or reference. This will cause an error, as the click binding expects a function value.

D)

: This solution will use a custom attribute instead of a data-bind attribute to apply the click binding. This is not supported by knockout and will not have any effect.


Contribute your Thoughts:

Jody
3 hours ago
I was going to say B) escapeLink($url) ?>, but now I'm not so sure. Looks like A is the way to go for secure URL output.
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Jacinta
4 days ago
The correct answer is A) escapeUrl($url) ?>. This is the most secure way to display a URL in a template, as it properly escapes the URL to prevent potential security vulnerabilities.
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Loreta
15 days ago
I'm not sure, but I think C) escapeHtml($url) ?> could also be a valid option
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William
17 days ago
I agree with Loreta, because we need to escape the URL for security
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Loreta
21 days ago
I think the answer is A) escapeUrl($url) ?>
upvoted 0 times
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